Егер (17) теңдеудің екі жағын y бөлсек, онда
y- y'+p(x)y1- =q(x) (18)
теңдеуін аламыз. z=y1- десек, z'=y- y'(1- )
Сонда y- y'= . Енді (18) теңдеуге қойсақ,
(19)
теңдеуі шығады. (19) теңдеудің z айнымалысына қарағанда сызықтық екені көрініп тұр. (17) теңдеудің де шешімін y=u·v түрінде іздейміз. Бернулли әдісі бойынша теңдеуді түрлендіріп ![](data:image/png;base64,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)
(20) системасын алуға болады. Бірінші теңдеуді шешіп v -ны, екінші теңдеуді шешіп u–ды табамыз.
Достарыңызбен бөлісу: |